2k-4(k-8)=2k-8(k+4)

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Solution for 2k-4(k-8)=2k-8(k+4) equation: 



2k-4(k-8)=2k-8(k+4)

We move all terms to the left:

2k-4(k-8)-(2k-8(k+4))=0

We multiply parentheses

2k-4k-(2k-8(k+4))+32=0



We calculate terms in parentheses: -(2k-8(k+4)), so:

2k-8(k+4)

We multiply parentheses

2k-8k-32

We add all the numbers together, and all the variables

-6k-32

Back to the equation:

-(-6k-32)



We add all the numbers together, and all the variables

-2k-(-6k-32)+32=0

We get rid of parentheses

-2k+6k+32+32=0

We add all the numbers together, and all the variables

4k+64=0

We move all terms containing k to the left, all other terms to the right

4k=-64

k=-64/4

k=-16

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