4(t-5)-(5t-4)=2(2t-3)-20

Solution for 4(t-5)-(5t-4)=2(2t-3)-20 equation:

4(t-5)-(5t-4)=2(2t-3)-20

We move all terms to the left:

4(t-5)-(5t-4)-(2(2t-3)-20)=0

We multiply parentheses

4t-(5t-4)-(2(2t-3)-20)-20=0

We get rid of parentheses

4t-5t-(2(2t-3)-20)+4-20=0


We calculate terms in parentheses: -(2(2t-3)-20), so:

2(2t-3)-20

We multiply parentheses

4t-6-20

We add all the numbers together, and all the variables

4t-26

Back to the equation:

-(4t-26)


We add all the numbers together, and all the variables

-1t-(4t-26)-16=0

We get rid of parentheses

-1t-4t+26-16=0

We add all the numbers together, and all the variables

-5t+10=0

We move all terms containing t to the left, all other terms to the right

-5t=-10

t=-10/-5

t=+2