5y+2(3y-1)=4y-(y+2)

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Solution for 5y+2(3y-1)=4y-(y+2) equation: 



5y+2(3y-1)=4y-(y+2)

We move all terms to the left:

5y+2(3y-1)-(4y-(y+2))=0

We multiply parentheses

5y+6y-(4y-(y+2))-2=0



We calculate terms in parentheses: -(4y-(y+2)), so:

4y-(y+2)

We get rid of parentheses

4y-y-2

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)



We add all the numbers together, and all the variables

11y-(3y-2)-2=0

We get rid of parentheses

11y-3y+2-2=0

We add all the numbers together, and all the variables

8y=0

y=0/8

y=0

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