4(t-12)=2(t+3)

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Solution for 4(t-12)=2(t+3) equation: 



4(t-12)=2(t+3)

We move all terms to the left:

4(t-12)-(2(t+3))=0

We multiply parentheses

4t-(2(t+3))-48=0



We calculate terms in parentheses: -(2(t+3)), so:

2(t+3)

We multiply parentheses

2t+6

Back to the equation:

-(2t+6)



We get rid of parentheses

4t-2t-6-48=0

We add all the numbers together, and all the variables

2t-54=0

We move all terms containing t to the left, all other terms to the right

2t=54

t=54/2

t=27

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