-(1)/4x-4+(3)/4x=(1)/2x+1

Solution for -(1)/4x-4+(3)/4x=(1)/2x+1 equation:

-(1)/4x-4+(3)/4x=(1)/2x+1

We move all terms to the left:

-(1)/4x-4+(3)/4x-((1)/2x+1)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x+1)!=0

x∈R


We get rid of parentheses

-1/4x+3/4x-1/2x-1-4=0

We calculate fractions


(6x-1)/8x^2+(-4x)/8x^2-1-4=0

We add all the numbers together, and all the variables

(6x-1)/8x^2+(-4x)/8x^2-5=0

We multiply all the terms by the denominator


(6x-1)+(-4x)-5*8x^2=0

Wy multiply elements

-40x^2+(6x-1)+(-4x)=0

We get rid of parentheses

-40x^2+6x-4x-1=0

We add all the numbers together, and all the variables

-40x^2+2x-1=0

a = -40; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-40)·(-1)
Δ = -156
Delta is less than zero, so there is no solution for the equation