4(t-1)=5(t+2)

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Solution for 4(t-1)=5(t+2) equation: 



4(t-1)=5(t+2)

We move all terms to the left:

4(t-1)-(5(t+2))=0

We multiply parentheses

4t-(5(t+2))-4=0



We calculate terms in parentheses: -(5(t+2)), so:

5(t+2)

We multiply parentheses

5t+10

Back to the equation:

-(5t+10)



We get rid of parentheses

4t-5t-10-4=0

We add all the numbers together, and all the variables

-1t-14=0

We move all terms containing t to the left, all other terms to the right

-t=14

t=14/-1

t=-14

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