((2+3x)/2)+((4-x)/7)=41/14

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Solution for ((2+3x)/2)+((4-x)/7)=41/14 equation: 



((2+3x)/2)+((4-x)/7)=41/14

We move all terms to the left:

((2+3x)/2)+((4-x)/7)-(41/14)=0

We add all the numbers together, and all the variables

((3x+2)/2)+((-1x+4)/7)-(+41/14)=0

We get rid of parentheses

((3x+2)/2)+((-1x+4)/7)-41/14=0

We calculate fractions


(((3x+2)*7)*14)/()+(((-1x+4)*2)*14)/()+()/()=0



We calculate terms in parentheses: +(((3x+2)*7)*14)/(), so:

((3x+2)*7)*14)/(

We multiply all the terms by the denominator


((3x+2)*7)*14)



We calculate terms in parentheses: +((3x+2)*7)*14), so:

(3x+2)*7)*14

We multiply parentheses

42x+

We add all the numbers together, and all the variables

42x

Back to the equation:

+(42x)



Back to the equation:

+(42x)





We calculate terms in parentheses: +(((-1x+4)*2)*14)/(), so:

((-1x+4)*2)*14)/(

We multiply all the terms by the denominator


((-1x+4)*2)*14)



We calculate terms in parentheses: +((-1x+4)*2)*14), so:

(-1x+4)*2)*14

We multiply parentheses

-14x+

We add all the numbers together, and all the variables

-14x

Back to the equation:

+(-14x)



We get rid of parentheses

-14x

Back to the equation:

+(-14x)



We add all the numbers together, and all the variables

42x+(-14x)+1=0

We get rid of parentheses

42x-14x+1=0

We add all the numbers together, and all the variables

28x+1=0

We move all terms containing x to the left, all other terms to the right

28x=-1

x=-1/28

x=-1/28

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