4(t-1)-5(4t-1)=27-7(6t+5)

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Solution for 4(t-1)-5(4t-1)=27-7(6t+5) equation: 



4(t-1)-5(4t-1)=27-7(6t+5)

We move all terms to the left:

4(t-1)-5(4t-1)-(27-7(6t+5))=0

We multiply parentheses

4t-20t-(27-7(6t+5))-4+5=0



We calculate terms in parentheses: -(27-7(6t+5)), so:

27-7(6t+5)

determiningTheFunctionDomain
-7(6t+5)+27

We multiply parentheses

-42t-35+27

We add all the numbers together, and all the variables

-42t-8

Back to the equation:

-(-42t-8)



We add all the numbers together, and all the variables

-16t-(-42t-8)+1=0

We get rid of parentheses

-16t+42t+8+1=0

We add all the numbers together, and all the variables

26t+9=0

We move all terms containing t to the left, all other terms to the right

26t=-9

t=-9/26

t=-9/26

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