3(x-2)-8=7x-2(1-x)

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Solution for 3(x-2)-8=7x-2(1-x) equation: 



3(x-2)-8=7x-2(1-x)

We move all terms to the left:

3(x-2)-8-(7x-2(1-x))=0

We add all the numbers together, and all the variables

3(x-2)-(7x-2(-1x+1))-8=0

We multiply parentheses

3x-(7x-2(-1x+1))-6-8=0



We calculate terms in parentheses: -(7x-2(-1x+1)), so:

7x-2(-1x+1)

We multiply parentheses

7x+2x-2

We add all the numbers together, and all the variables

9x-2

Back to the equation:

-(9x-2)



We add all the numbers together, and all the variables

3x-(9x-2)-14=0

We get rid of parentheses

3x-9x+2-14=0

We add all the numbers together, and all the variables

-6x-12=0

We move all terms containing x to the left, all other terms to the right

-6x=12

x=12/-6

x=-2

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