4(t+20)=1/5(20t+400

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Solution for 4(t+20)=1/5(20t+400 equation: 



4(t+20)=1/5(20t+400

We move all terms to the left:

4(t+20)-(1/5(20t+400)=0



Domain of the equation: 5(20t+400)!=0

t∈R



We multiply parentheses

4t-(1/5(20t+400)+80=0

We multiply all the terms by the denominator


4t*5(20t+400)+80-(1=0

We add all the numbers together, and all the variables

4t*5(20t+400)=0

Wy multiply elements

20t^2(2=0

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