9(i+3)/2=3+6i

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Solution for 9(i+3)/2=3+6i equation: 



9(i+3)/2=3+6i

We move all terms to the left:

9(i+3)/2-(3+6i)=0

We add all the numbers together, and all the variables

9(i+3)/2-(6i+3)=0

We get rid of parentheses

9(i+3)/2-6i-3=0

We multiply all the terms by the denominator


9(i+3)-6i*2-3*2=0

We add all the numbers together, and all the variables

9(i+3)-6i*2-6=0

We multiply parentheses

9i-6i*2+27-6=0

Wy multiply elements

9i-12i+27-6=0

We add all the numbers together, and all the variables

-3i+21=0

We move all terms containing i to the left, all other terms to the right

-3i=-21

i=-21/-3

i=+7

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