4(t+2)-3=7(t+5)

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Solution for 4(t+2)-3=7(t+5) equation: 



4(t+2)-3=7(t+5)

We move all terms to the left:

4(t+2)-3-(7(t+5))=0

We multiply parentheses

4t-(7(t+5))+8-3=0



We calculate terms in parentheses: -(7(t+5)), so:

7(t+5)

We multiply parentheses

7t+35

Back to the equation:

-(7t+35)



We add all the numbers together, and all the variables

4t-(7t+35)+5=0

We get rid of parentheses

4t-7t-35+5=0

We add all the numbers together, and all the variables

-3t-30=0

We move all terms containing t to the left, all other terms to the right

-3t=30

t=30/-3

t=-10

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