x(3x-2)=(3x+6)(x-8)

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Solution for x(3x-2)=(3x+6)(x-8) equation: 



x(3x-2)=(3x+6)(x-8)

We move all terms to the left:

x(3x-2)-((3x+6)(x-8))=0

We multiply parentheses

3x^2-2x-((3x+6)(x-8))=0

We multiply parentheses ..

3x^2-((+3x^2-24x+6x-48))-2x=0



We calculate terms in parentheses: -((+3x^2-24x+6x-48)), so:

(+3x^2-24x+6x-48)

We get rid of parentheses

3x^2-24x+6x-48

We add all the numbers together, and all the variables

3x^2-18x-48

Back to the equation:

-(3x^2-18x-48)



We add all the numbers together, and all the variables

3x^2-2x-(3x^2-18x-48)=0

We get rid of parentheses

3x^2-3x^2-2x+18x+48=0

We add all the numbers together, and all the variables

16x+48=0

We move all terms containing x to the left, all other terms to the right

16x=-48

x=-48/16

x=-3

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