4(r-1)+4r=2(3r+1)

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Solution for 4(r-1)+4r=2(3r+1) equation: 



4(r-1)+4r=2(3r+1)

We move all terms to the left:

4(r-1)+4r-(2(3r+1))=0

We add all the numbers together, and all the variables

4r+4(r-1)-(2(3r+1))=0

We multiply parentheses

4r+4r-(2(3r+1))-4=0



We calculate terms in parentheses: -(2(3r+1)), so:

2(3r+1)

We multiply parentheses

6r+2

Back to the equation:

-(6r+2)



We add all the numbers together, and all the variables

8r-(6r+2)-4=0

We get rid of parentheses

8r-6r-2-4=0

We add all the numbers together, and all the variables

2r-6=0

We move all terms containing r to the left, all other terms to the right

2r=6

r=6/2

r=3

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