4(r+1)+4r=2(3r-1)

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Solution for 4(r+1)+4r=2(3r-1) equation: 



4(r+1)+4r=2(3r-1)

We move all terms to the left:

4(r+1)+4r-(2(3r-1))=0

We add all the numbers together, and all the variables

4r+4(r+1)-(2(3r-1))=0

We multiply parentheses

4r+4r-(2(3r-1))+4=0



We calculate terms in parentheses: -(2(3r-1)), so:

2(3r-1)

We multiply parentheses

6r-2

Back to the equation:

-(6r-2)



We add all the numbers together, and all the variables

8r-(6r-2)+4=0

We get rid of parentheses

8r-6r+2+4=0

We add all the numbers together, and all the variables

2r+6=0

We move all terms containing r to the left, all other terms to the right

2r=-6

r=-6/2

r=-3

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