4(r+3)=1

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Solution for 4(r+3)=1 equation: 



4(r+3)=1

We move all terms to the left:

4(r+3)-(1)=0

We multiply parentheses

4r+12-1=0

We add all the numbers together, and all the variables

4r+11=0

We move all terms containing r to the left, all other terms to the right

4r=-11

r=-11/4

r=-2+3/4

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