4(2x-3)-2(x-5)=3(x+7)-8

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Solution for 4(2x-3)-2(x-5)=3(x+7)-8 equation: 



4(2x-3)-2(x-5)=3(x+7)-8

We move all terms to the left:

4(2x-3)-2(x-5)-(3(x+7)-8)=0

We multiply parentheses

8x-2x-(3(x+7)-8)-12+10=0



We calculate terms in parentheses: -(3(x+7)-8), so:

3(x+7)-8

We multiply parentheses

3x+21-8

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We add all the numbers together, and all the variables

6x-(3x+13)-2=0

We get rid of parentheses

6x-3x-13-2=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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