4(r+2)=6(3-2)

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Solution for 4(r+2)=6(3-2) equation: 



4(r+2)=6(3-2)

We move all terms to the left:

4(r+2)-(6(3-2))=0

We add all the numbers together, and all the variables

4(r+2)-(61)=0

We add all the numbers together, and all the variables

4(r+2)-61=0

We multiply parentheses

4r+8-61=0

We add all the numbers together, and all the variables

4r-53=0

We move all terms containing r to the left, all other terms to the right

4r=53

r=53/4

r=13+1/4

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