5x2+7x=108

Solution for 5x2+7x=108 equation:

5x^2+7x=108

We move all terms to the left:

5x^2+7x-(108)=0

a = 5; b = 7; c = -108;
Δ = b2-4ac
Δ = 72-4·5·(-108)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-47}{2*5}=\frac{-54}{10}
=-5+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+47}{2*5}=\frac{40}{10}
=4
$