4(r+2)=3r-6(2r-10)

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Solution for 4(r+2)=3r-6(2r-10) equation: 



4(r+2)=3r-6(2r-10)

We move all terms to the left:

4(r+2)-(3r-6(2r-10))=0

We multiply parentheses

4r-(3r-6(2r-10))+8=0



We calculate terms in parentheses: -(3r-6(2r-10)), so:

3r-6(2r-10)

We multiply parentheses

3r-12r+60

We add all the numbers together, and all the variables

-9r+60

Back to the equation:

-(-9r+60)



We get rid of parentheses

4r+9r-60+8=0

We add all the numbers together, and all the variables

13r-52=0

We move all terms containing r to the left, all other terms to the right

13r=52

r=52/13

r=4

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