4(4x-3)=x-2(12-8x)

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Solution for 4(4x-3)=x-2(12-8x) equation: 



4(4x-3)=x-2(12-8x)

We move all terms to the left:

4(4x-3)-(x-2(12-8x))=0

We add all the numbers together, and all the variables

4(4x-3)-(x-2(-8x+12))=0

We multiply parentheses

16x-(x-2(-8x+12))-12=0



We calculate terms in parentheses: -(x-2(-8x+12)), so:

x-2(-8x+12)

We multiply parentheses

x+16x-24

We add all the numbers together, and all the variables

17x-24

Back to the equation:

-(17x-24)



We get rid of parentheses

16x-17x+24-12=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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