5x-(3x+4)+92=13/3+9x-2x+12

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Solution for 5x-(3x+4)+92=13/3+9x-2x+12 equation: 



5x-(3x+4)+92=13/3+9x-2x+12

We move all terms to the left:

5x-(3x+4)+92-(13/3+9x-2x+12)=0



Domain of the equation: 3+9x-2x+12)!=0

We move all terms containing x to the left, all other terms to the right

9x-2x+12)!=-3

x∈R



We add all the numbers together, and all the variables

5x-(3x+4)-(7x+13/3+12)+92=0

We get rid of parentheses

5x-3x-7x-4-12+92-13/3=0

We multiply all the terms by the denominator


5x*3-3x*3-7x*3-13-4*3-12*3+92*3=0

We add all the numbers together, and all the variables

5x*3-3x*3-7x*3+215=0

Wy multiply elements

15x-9x-21x+215=0

We add all the numbers together, and all the variables

-15x+215=0

We move all terms containing x to the left, all other terms to the right

-15x=-215

x=-215/-15

x=14+1/3

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