4(n-6)+2n=3(n+3)

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Solution for 4(n-6)+2n=3(n+3) equation: 



4(n-6)+2n=3(n+3)

We move all terms to the left:

4(n-6)+2n-(3(n+3))=0

We add all the numbers together, and all the variables

2n+4(n-6)-(3(n+3))=0

We multiply parentheses

2n+4n-(3(n+3))-24=0



We calculate terms in parentheses: -(3(n+3)), so:

3(n+3)

We multiply parentheses

3n+9

Back to the equation:

-(3n+9)



We add all the numbers together, and all the variables

6n-(3n+9)-24=0

We get rid of parentheses

6n-3n-9-24=0

We add all the numbers together, and all the variables

3n-33=0

We move all terms containing n to the left, all other terms to the right

3n=33

n=33/3

n=11

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