(-8x2+10x+7)+(-9x2+10x+9)=0

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Solution for (-8x2+10x+7)+(-9x2+10x+9)=0 equation:



(-8x^2+10x+7)+(-9x^2+10x+9)=0
We get rid of parentheses
-8x^2-9x^2+10x+10x+7+9=0
We add all the numbers together, and all the variables
-17x^2+20x+16=0
a = -17; b = 20; c = +16;
Δ = b2-4ac
Δ = 202-4·(-17)·16
Δ = 1488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1488}=\sqrt{16*93}=\sqrt{16}*\sqrt{93}=4\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{93}}{2*-17}=\frac{-20-4\sqrt{93}}{-34} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{93}}{2*-17}=\frac{-20+4\sqrt{93}}{-34} $

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