4(n-4)-2(n-2)=-8n

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Solution for 4(n-4)-2(n-2)=-8n equation: 



4(n-4)-2(n-2)=-8n

We move all terms to the left:

4(n-4)-2(n-2)-(-8n)=0

We multiply parentheses

4n-2n-(-8n)-16+4=0

We get rid of parentheses

4n-2n+8n-16+4=0

We add all the numbers together, and all the variables

10n-12=0

We move all terms containing n to the left, all other terms to the right

10n=12

n=12/10

n=1+1/5

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