4(n-3)+6n=68

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Solution for 4(n-3)+6n=68 equation: 



4(n-3)+6n=68

We move all terms to the left:

4(n-3)+6n-(68)=0

We add all the numbers together, and all the variables

6n+4(n-3)-68=0

We multiply parentheses

6n+4n-12-68=0

We add all the numbers together, and all the variables

10n-80=0

We move all terms containing n to the left, all other terms to the right

10n=80

n=80/10

n=8

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