4(n-2)=5(n-3)

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Solution for 4(n-2)=5(n-3) equation: 



4(n-2)=5(n-3)

We move all terms to the left:

4(n-2)-(5(n-3))=0

We multiply parentheses

4n-(5(n-3))-8=0



We calculate terms in parentheses: -(5(n-3)), so:

5(n-3)

We multiply parentheses

5n-15

Back to the equation:

-(5n-15)



We get rid of parentheses

4n-5n+15-8=0

We add all the numbers together, and all the variables

-1n+7=0

We move all terms containing n to the left, all other terms to the right

-n=-7

n=-7/-1

n=+7

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