K-2=3(y-2)

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Solution for K-2=3(y-2) equation: 



-2=3(K-2)

We move all terms to the left:

-2-(3(K-2))=0



We calculate terms in parentheses: -(3(K-2)), so:

3(K-2)

We multiply parentheses

3K-6

Back to the equation:

-(3K-6)



We get rid of parentheses

-3K+6-2=0

We add all the numbers together, and all the variables

-3K+4=0

We move all terms containing K to the left, all other terms to the right

-3K=-4

K=-4/-3

K=1+1/3

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