4(n-10)=7(2-2n)

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Solution for 4(n-10)=7(2-2n) equation: 



4(n-10)=7(2-2n)

We move all terms to the left:

4(n-10)-(7(2-2n))=0

We add all the numbers together, and all the variables

4(n-10)-(7(-2n+2))=0

We multiply parentheses

4n-(7(-2n+2))-40=0



We calculate terms in parentheses: -(7(-2n+2)), so:

7(-2n+2)

We multiply parentheses

-14n+14

Back to the equation:

-(-14n+14)



We get rid of parentheses

4n+14n-14-40=0

We add all the numbers together, and all the variables

18n-54=0

We move all terms containing n to the left, all other terms to the right

18n=54

n=54/18

n=3

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