If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x(3x-29)=2x-2
We move all terms to the left:
2x(3x-29)-(2x-2)=0
We multiply parentheses
6x^2-58x-(2x-2)=0
We get rid of parentheses
6x^2-58x-2x+2=0
We add all the numbers together, and all the variables
6x^2-60x+2=0
a = 6; b = -60; c = +2;
Δ = b2-4ac
Δ = -602-4·6·2
Δ = 3552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3552}=\sqrt{16*222}=\sqrt{16}*\sqrt{222}=4\sqrt{222}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{222}}{2*6}=\frac{60-4\sqrt{222}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{222}}{2*6}=\frac{60+4\sqrt{222}}{12} $
| 42=-6(x-9) | | 5/y-11=9 | | 6/7t-12=13/4t+15 | | 5h+15-3h=32h= | | 9x+1=5x+12=10x-37 | | 6x+3-4x=11 | | y=2(10)^10 | | b+62=85 | | b+b+b+6=b+22 | | y=10(2)^10 | | 3(k-18)=-12 | | 5(x–3)=30 | | -(7x+2)=-15 | | n^2-2n-8=7 | | 1,820+x(145.50)=3,711.50 | | 30x-25x2=9 | | 24+4y-4y=-24 | | 7-n/6=4 | | 18r−13r=5 | | -6x-10=-28+3x | | -31=4-7n | | 2(3x+4)+4x-2x=72 | | 4x+12=3×+24 | | 12=x/3+8 | | -6(x–3)=54 | | y/3+-16=-19 | | 9y-14=4 | | 74–b=53 | | 60+3y=40+2y | | q-42=-37 | | y=3000(1.04)^10 | | Y=32x-16 |