4(n+3)=5(2+n)

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Solution for 4(n+3)=5(2+n) equation: 



4(n+3)=5(2+n)

We move all terms to the left:

4(n+3)-(5(2+n))=0

We add all the numbers together, and all the variables

4(n+3)-(5(n+2))=0

We multiply parentheses

4n-(5(n+2))+12=0



We calculate terms in parentheses: -(5(n+2)), so:

5(n+2)

We multiply parentheses

5n+10

Back to the equation:

-(5n+10)



We get rid of parentheses

4n-5n-10+12=0

We add all the numbers together, and all the variables

-1n+2=0

We move all terms containing n to the left, all other terms to the right

-n=-2

n=-2/-1

n=+2

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