4(n+3)=-28

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Solution for 4(n+3)=-28 equation: 



4(n+3)=-28

We move all terms to the left:

4(n+3)-(-28)=0

We add all the numbers together, and all the variables

4(n+3)+28=0

We multiply parentheses

4n+12+28=0

We add all the numbers together, and all the variables

4n+40=0

We move all terms containing n to the left, all other terms to the right

4n=-40

n=-40/4

n=-10

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