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5/3x+11=x+2
We move all terms to the left:
5/3x+11-(x+2)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
5/3x-x-2+11=0
We multiply all the terms by the denominator
-x*3x-2*3x+11*3x+5=0
Wy multiply elements
-3x^2-6x+33x+5=0
We add all the numbers together, and all the variables
-3x^2+27x+5=0
a = -3; b = 27; c = +5;
Δ = b2-4ac
Δ = 272-4·(-3)·5
Δ = 789
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{789}}{2*-3}=\frac{-27-\sqrt{789}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{789}}{2*-3}=\frac{-27+\sqrt{789}}{-6} $
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