4(n+2)=2(10-n)

Solution for 4(n+2)=2(10-n) equation:

4(n+2)=2(10-n)

We move all terms to the left:

4(n+2)-(2(10-n))=0

We add all the numbers together, and all the variables

4(n+2)-(2(-1n+10))=0

We multiply parentheses

4n-(2(-1n+10))+8=0


We calculate terms in parentheses: -(2(-1n+10)), so:

2(-1n+10)

We multiply parentheses

-2n+20

Back to the equation:

-(-2n+20)


We get rid of parentheses

4n+2n-20+8=0

We add all the numbers together, and all the variables

6n-12=0

We move all terms containing n to the left, all other terms to the right

6n=12

n=12/6

n=2