1/3(24x-9)-4x=0.75(16-12x)-2

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Solution for 1/3(24x-9)-4x=0.75(16-12x)-2 equation: 



1/3(24x-9)-4x=0.75(16-12x)-2

We move all terms to the left:

1/3(24x-9)-4x-(0.75(16-12x)-2)=0



Domain of the equation: 3(24x-9)!=0

x∈R



We add all the numbers together, and all the variables

1/3(24x-9)-4x-(0.75(-12x+16)-2)=0

We add all the numbers together, and all the variables

-4x+1/3(24x-9)-(0.75(-12x+16)-2)=0

We multiply all the terms by the denominator


-4x*3(24x-9)-((0.75(-12x+16)-2))*3(24x-9)+1=0



We calculate terms in parentheses: -((0.75(-12x+16)-2))*3(24x-9), so:

(0.75(-12x+16)-2))*3(24x-9



Wy multiply elements

-12x^2(2-((0.75(-12x+16)-2))*3(24x-9)+1=0

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