4(n+12)=3-n

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Solution for 4(n+12)=3-n equation: 



4(n+12)=3-n

We move all terms to the left:

4(n+12)-(3-n)=0

We add all the numbers together, and all the variables

4(n+12)-(-1n+3)=0

We multiply parentheses

4n-(-1n+3)+48=0

We get rid of parentheses

4n+1n-3+48=0

We add all the numbers together, and all the variables

5n+45=0

We move all terms containing n to the left, all other terms to the right

5n=-45

n=-45/5

n=-9

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