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(2x+15)(2x+9)=567
We move all terms to the left:
(2x+15)(2x+9)-(567)=0
We multiply parentheses ..
(+4x^2+18x+30x+135)-567=0
We get rid of parentheses
4x^2+18x+30x+135-567=0
We add all the numbers together, and all the variables
4x^2+48x-432=0
a = 4; b = 48; c = -432;
Δ = b2-4ac
Δ = 482-4·4·(-432)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-96}{2*4}=\frac{-144}{8} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+96}{2*4}=\frac{48}{8} =6 $
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