4(n+1)=1-(n-3)

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Solution for 4(n+1)=1-(n-3) equation: 



4(n+1)=1-(n-3)

We move all terms to the left:

4(n+1)-(1-(n-3))=0

We multiply parentheses

4n-(1-(n-3))+4=0



We calculate terms in parentheses: -(1-(n-3)), so:

1-(n-3)

determiningTheFunctionDomain
-(n-3)+1

We get rid of parentheses

-n+3+1

We add all the numbers together, and all the variables

-1n+4

Back to the equation:

-(-1n+4)



We get rid of parentheses

4n+1n-4+4=0

We add all the numbers together, and all the variables

5n=0

n=0/5

n=0

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