-7r+40=2(1-7r)+3

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Solution for -7r+40=2(1-7r)+3 equation: 



-7r+40=2(1-7r)+3

We move all terms to the left:

-7r+40-(2(1-7r)+3)=0

We add all the numbers together, and all the variables

-7r-(2(-7r+1)+3)+40=0



We calculate terms in parentheses: -(2(-7r+1)+3), so:

2(-7r+1)+3

We multiply parentheses

-14r+2+3

We add all the numbers together, and all the variables

-14r+5

Back to the equation:

-(-14r+5)



We get rid of parentheses

-7r+14r-5+40=0

We add all the numbers together, and all the variables

7r+35=0

We move all terms containing r to the left, all other terms to the right

7r=-35

r=-35/7

r=-5

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