4(n+1)+(n+3)=5(n+1)+12

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Solution for 4(n+1)+(n+3)=5(n+1)+12 equation: 



4(n+1)+(n+3)=5(n+1)+12

We move all terms to the left:

4(n+1)+(n+3)-(5(n+1)+12)=0

We multiply parentheses

4n+(n+3)-(5(n+1)+12)+4=0

We get rid of parentheses

4n+n-(5(n+1)+12)+3+4=0



We calculate terms in parentheses: -(5(n+1)+12), so:

5(n+1)+12

We multiply parentheses

5n+5+12

We add all the numbers together, and all the variables

5n+17

Back to the equation:

-(5n+17)



We add all the numbers together, and all the variables

5n-(5n+17)+7=0

We get rid of parentheses

5n-5n-17+7=0

We add all the numbers together, and all the variables

-10!=0

There is no solution for this equation

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