6y-2+2(4y+4)=-2(y+3)

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Solution for 6y-2+2(4y+4)=-2(y+3) equation: 



6y-2+2(4y+4)=-2(y+3)

We move all terms to the left:

6y-2+2(4y+4)-(-2(y+3))=0

We multiply parentheses

6y+8y-(-2(y+3))+8-2=0



We calculate terms in parentheses: -(-2(y+3)), so:

-2(y+3)

We multiply parentheses

-2y-6

Back to the equation:

-(-2y-6)



We add all the numbers together, and all the variables

14y-(-2y-6)+6=0

We get rid of parentheses

14y+2y+6+6=0

We add all the numbers together, and all the variables

16y+12=0

We move all terms containing y to the left, all other terms to the right

16y=-12

y=-12/16

y=-3/4

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