4(m-5)=6(m+1)

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Solution for 4(m-5)=6(m+1) equation: 



4(m-5)=6(m+1)

We move all terms to the left:

4(m-5)-(6(m+1))=0

We multiply parentheses

4m-(6(m+1))-20=0



We calculate terms in parentheses: -(6(m+1)), so:

6(m+1)

We multiply parentheses

6m+6

Back to the equation:

-(6m+6)



We get rid of parentheses

4m-6m-6-20=0

We add all the numbers together, and all the variables

-2m-26=0

We move all terms containing m to the left, all other terms to the right

-2m=26

m=26/-2

m=-13

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