3(x-2)+5x=9-4(x+3)

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Solution for 3(x-2)+5x=9-4(x+3) equation: 



3(x-2)+5x=9-4(x+3)

We move all terms to the left:

3(x-2)+5x-(9-4(x+3))=0

We add all the numbers together, and all the variables

5x+3(x-2)-(9-4(x+3))=0

We multiply parentheses

5x+3x-(9-4(x+3))-6=0



We calculate terms in parentheses: -(9-4(x+3)), so:

9-4(x+3)

determiningTheFunctionDomain
-4(x+3)+9

We multiply parentheses

-4x-12+9

We add all the numbers together, and all the variables

-4x-3

Back to the equation:

-(-4x-3)



We add all the numbers together, and all the variables

8x-(-4x-3)-6=0

We get rid of parentheses

8x+4x+3-6=0

We add all the numbers together, and all the variables

12x-3=0

We move all terms containing x to the left, all other terms to the right

12x=3

x=3/12

x=1/4

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