4(m-10)=8(m+1)+12

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Solution for 4(m-10)=8(m+1)+12 equation: 



4(m-10)=8(m+1)+12

We move all terms to the left:

4(m-10)-(8(m+1)+12)=0

We multiply parentheses

4m-(8(m+1)+12)-40=0



We calculate terms in parentheses: -(8(m+1)+12), so:

8(m+1)+12

We multiply parentheses

8m+8+12

We add all the numbers together, and all the variables

8m+20

Back to the equation:

-(8m+20)



We get rid of parentheses

4m-8m-20-40=0

We add all the numbers together, and all the variables

-4m-60=0

We move all terms containing m to the left, all other terms to the right

-4m=60

m=60/-4

m=-15

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