4(2n+5)=9(7n+3)+8

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Solution for 4(2n+5)=9(7n+3)+8 equation: 



4(2n+5)=9(7n+3)+8

We move all terms to the left:

4(2n+5)-(9(7n+3)+8)=0

We multiply parentheses

8n-(9(7n+3)+8)+20=0



We calculate terms in parentheses: -(9(7n+3)+8), so:

9(7n+3)+8

We multiply parentheses

63n+27+8

We add all the numbers together, and all the variables

63n+35

Back to the equation:

-(63n+35)



We get rid of parentheses

8n-63n-35+20=0

We add all the numbers together, and all the variables

-55n-15=0

We move all terms containing n to the left, all other terms to the right

-55n=15

n=15/-55

n=-3/11

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