4(m+7)=2(11-m)

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Solution for 4(m+7)=2(11-m) equation: 



4(m+7)=2(11-m)

We move all terms to the left:

4(m+7)-(2(11-m))=0

We add all the numbers together, and all the variables

4(m+7)-(2(-1m+11))=0

We multiply parentheses

4m-(2(-1m+11))+28=0



We calculate terms in parentheses: -(2(-1m+11)), so:

2(-1m+11)

We multiply parentheses

-2m+22

Back to the equation:

-(-2m+22)



We get rid of parentheses

4m+2m-22+28=0

We add all the numbers together, and all the variables

6m+6=0

We move all terms containing m to the left, all other terms to the right

6m=-6

m=-6/6

m=-1

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