4(m+3)=3(2m-2)

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Solution for 4(m+3)=3(2m-2) equation: 



4(m+3)=3(2m-2)

We move all terms to the left:

4(m+3)-(3(2m-2))=0

We multiply parentheses

4m-(3(2m-2))+12=0



We calculate terms in parentheses: -(3(2m-2)), so:

3(2m-2)

We multiply parentheses

6m-6

Back to the equation:

-(6m-6)



We get rid of parentheses

4m-6m+6+12=0

We add all the numbers together, and all the variables

-2m+18=0

We move all terms containing m to the left, all other terms to the right

-2m=-18

m=-18/-2

m=+9

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