4(m+3)=-7(4-2m)

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Solution for 4(m+3)=-7(4-2m) equation: 



4(m+3)=-7(4-2m)

We move all terms to the left:

4(m+3)-(-7(4-2m))=0

We add all the numbers together, and all the variables

4(m+3)-(-7(-2m+4))=0

We multiply parentheses

4m-(-7(-2m+4))+12=0



We calculate terms in parentheses: -(-7(-2m+4)), so:

-7(-2m+4)

We multiply parentheses

14m-28

Back to the equation:

-(14m-28)



We get rid of parentheses

4m-14m+28+12=0

We add all the numbers together, and all the variables

-10m+40=0

We move all terms containing m to the left, all other terms to the right

-10m=-40

m=-40/-10

m=+4

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