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6x+26x-10=8(4x+10)6x+26x-10=8(4x+10)
We move all terms to the left:
6x+26x-10-(8(4x+10)6x+26x-10)=0
We add all the numbers together, and all the variables
32x-(8(4x+10)6x+26x-10)-10=0
We calculate terms in parentheses: -(8(4x+10)6x+26x-10), so:We get rid of parentheses
8(4x+10)6x+26x-10
We add all the numbers together, and all the variables
26x+8(4x+10)6x-10
We multiply parentheses
192x^2+26x+480x-10
We add all the numbers together, and all the variables
192x^2+506x-10
Back to the equation:
-(192x^2+506x-10)
-192x^2+32x-506x+10-10=0
We add all the numbers together, and all the variables
-192x^2-474x=0
a = -192; b = -474; c = 0;
Δ = b2-4ac
Δ = -4742-4·(-192)·0
Δ = 224676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{224676}=474$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-474)-474}{2*-192}=\frac{0}{-384} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-474)+474}{2*-192}=\frac{948}{-384} =-2+15/32 $
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