4(m+3)+7=4m+19m=

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Solution for 4(m+3)+7=4m+19m= equation: 



4(m+3)+7=4m+19m=

We move all terms to the left:

4(m+3)+7-(4m+19m)=0

We add all the numbers together, and all the variables

4(m+3)-(+23m)+7=0

We multiply parentheses

4m-(+23m)+12+7=0

We get rid of parentheses

4m-23m+12+7=0

We add all the numbers together, and all the variables

-19m+19=0

We move all terms containing m to the left, all other terms to the right

-19m=-19

m=-19/-19

m=1

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